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Last updated on October 17, 2025
We use the derivative of sin^x, as a measuring tool for how the sine function raised to the power x changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now talk about the derivative of sin^x in detail.
We now understand the derivative of sinx. It is commonly represented as d/dx (sinx) or (sinx)'. The function sinx has a clearly defined derivative, indicating it is differentiable within its domain.
The key concepts are mentioned below:
Sine Function: (sin(x) is a basic trigonometric function).
Exponent Rule: Rule for differentiating functions raised to a power.
Chain Rule: Used for differentiating composite functions like sinx.
The derivative of sinx can be denoted as d/dx (sinx) or (sinx)'.
The formula we use to differentiate sinx is: d/dx (sinx) = x * sin(x-1) * cos(x)
The formula applies to all x where sin(x) is defined.
We can derive the derivative of sinx using proofs. To show this, we will use the trigonometric identities along with the rules of differentiation.
There are several methods we use to prove this, such as:
We will now demonstrate that the differentiation of sin^x results in x*sin^(x-1)*cos(x) using the above-mentioned methods:
The derivative of sin^x can be proved using the First Principle, which expresses the derivative as the limit of the difference quotient. To find the derivative of sinx using the first principle, we will consider f(x) = sinx. Its derivative can be expressed as the following limit. f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1) Given that f(x) = sinx, we write f(x + h) = (sin (x + h))x. Substituting these into equation (1), f'(x) = limₕ→₀ [(sin(x + h))x - (sin(x))x] / h Using binomial expansion and limit properties, we simplify: f'(x) ≈ x*sin^(x-1)*cos(x) Hence, proved.
To prove the differentiation of sinx using the chain rule, We use the formula: Let u = sin(x), then sinx = ux Using the chain rule: d/dx [ux] = x * u(x-1) * du/dx Since du/dx = cos(x), d/dx (sinx) = x*sin(x-1)*cos(x)
We will now prove the derivative of sinx using the product rule. The step-by-step process is demonstrated below: Here, we use the formula, sinx = sin(x) * sin(x-1) Given that, u = sin(x) and v = sin(x-1) Using the product rule formula: d/dx [u*v] = u'v + uv' u' = d/dx (sin x) = cos x (substitute u = sin x) v' = (x-1) * sin(x-2) * cos(x) (using power and chain rules) Again, use the product rule formula: d/dx (sinx) = u'v + uv' Let’s substitute u = sin(x), u' = cos(x), v = sin^(x-1), and v' = (x-1)*sin(x-2)*cos(x) When we simplify each term: d/dx (sin^x) = x*sin(x-1)*cos(x)
When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky. To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like sinx.
For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x). Similarly, the third derivative, f′′′(x) is the result of the second derivative and this pattern continues.
For the nth Derivative of sinx, we generally use fn(x) for the nth derivative of a function f(x) which tells us the change in the rate of change. (continuing for higher-order derivatives).
When x is an integer, the derivative's behavior might be simpler due to the power rule.
When x = 1, the derivative of sinx = cos(x), which is the derivative of sin(x).
Students frequently make mistakes when differentiating sinx. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of sin^3(x).
Here, we have f(x) = sin^3(x). Using the chain rule, f'(x) = 3*sin^2(x)*cos(x) Thus, the derivative of the specified function is 3*sin^2(x)*cos(x).
We find the derivative of the given function by applying the chain rule.
The first step is finding the derivative of the outer function and then multiplying by the derivative of the inner function to get the final result.
An amusement park ride follows a path defined by y = sin^x where y represents the ride's height at a distance x. If x = π/6 meters, measure the rate of change of the ride's height.
We have y = sin^x (height of the ride)...(1) Now, we will differentiate the equation (1) Take the derivative sin^x: dy/dx = x*sin^(x-1)*cos(x) Given x = π/6 (substitute this into the derivative) dy/dx = π/6*sin^(π/6 - 1)*cos(π/6) = π/6*sin^(-5/6)*√3/2 Hence, we get the rate of change of the ride's height at x = π/6.
We find the rate of change of the ride's height at x = π/6 by substituting into the derivative, which gives us the rate at which the height changes concerning the horizontal distance.
Derive the second derivative of the function y = sin^x.
The first step is to find the first derivative, dy/dx = x*sin^(x-1)*cos(x)...(1) Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [x*sin^(x-1)*cos(x)] Here we use the product rule and chain rule, d²y/dx² = sin^(x-1)*cos(x) + x*(x-1)*sin^(x-2)*cos²(x) - x*sin^(x-1)*sin(x) Therefore, the second derivative of the function y = sin^x is obtained.
We use the step-by-step process, where we start with the first derivative.
Using the product and chain rules, we differentiate further to find the second derivative.
Prove: d/dx (sin^2(x)) = 2*sin(x)*cos(x).
Let’s start using the chain rule: Consider y = sin^2(x) = [sin(x)]^2 To differentiate, we use the chain rule: dy/dx = 2*sin(x)*d/dx [sin(x)] Since the derivative of sin(x) is cos(x), dy/dx = 2*sin(x)*cos(x) Substituting y = sin^2(x), d/dx (sin^2(x)) = 2*sin(x)*cos(x) Hence proved.
In this step-by-step process, we used the chain rule to differentiate the equation.
Then, we replace sin(x) with its derivative.
As a final step, we substitute y = sin2(x) to derive the equation.
Solve: d/dx (sin^x/x)
To differentiate the function, we use the quotient rule: d/dx (sin^x/x) = (d/dx (sin^x) * x - sin^x * d/dx(x)) / x² We will substitute d/dx (sin^x) = x*sin^(x-1)*cos(x) and d/dx (x) = 1 = (x*sin^(x-1)*cos(x)*x - sin^x*1) / x² = (x²*sin^(x-1)*cos(x) - sin^x) / x² Therefore, d/dx (sin^x/x) = x*sin^(x-1)*cos(x) - sin^x/x²
In this process, we differentiate the given function using the product rule and quotient rule.
As a final step, we simplify the equation to obtain the final result.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.